3.404 \(\int \frac{(a+b x^2)^2 (c+d x^2)^2}{x^{3/2}} \, dx\)

Optimal. Leaf size=95 \[ \frac{2}{7} x^{7/2} \left (a^2 d^2+4 a b c d+b^2 c^2\right )-\frac{2 a^2 c^2}{\sqrt{x}}+\frac{4}{11} b d x^{11/2} (a d+b c)+\frac{4}{3} a c x^{3/2} (a d+b c)+\frac{2}{15} b^2 d^2 x^{15/2} \]

[Out]

(-2*a^2*c^2)/Sqrt[x] + (4*a*c*(b*c + a*d)*x^(3/2))/3 + (2*(b^2*c^2 + 4*a*b*c*d + a^2*d^2)*x^(7/2))/7 + (4*b*d*
(b*c + a*d)*x^(11/2))/11 + (2*b^2*d^2*x^(15/2))/15

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Rubi [A]  time = 0.0475267, antiderivative size = 95, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.042, Rules used = {448} \[ \frac{2}{7} x^{7/2} \left (a^2 d^2+4 a b c d+b^2 c^2\right )-\frac{2 a^2 c^2}{\sqrt{x}}+\frac{4}{11} b d x^{11/2} (a d+b c)+\frac{4}{3} a c x^{3/2} (a d+b c)+\frac{2}{15} b^2 d^2 x^{15/2} \]

Antiderivative was successfully verified.

[In]

Int[((a + b*x^2)^2*(c + d*x^2)^2)/x^(3/2),x]

[Out]

(-2*a^2*c^2)/Sqrt[x] + (4*a*c*(b*c + a*d)*x^(3/2))/3 + (2*(b^2*c^2 + 4*a*b*c*d + a^2*d^2)*x^(7/2))/7 + (4*b*d*
(b*c + a*d)*x^(11/2))/11 + (2*b^2*d^2*x^(15/2))/15

Rule 448

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.), x_Symbol] :> Int[ExpandI
ntegrand[(e*x)^m*(a + b*x^n)^p*(c + d*x^n)^q, x], x] /; FreeQ[{a, b, c, d, e, m, n}, x] && NeQ[b*c - a*d, 0] &
& IGtQ[p, 0] && IGtQ[q, 0]

Rubi steps

\begin{align*} \int \frac{\left (a+b x^2\right )^2 \left (c+d x^2\right )^2}{x^{3/2}} \, dx &=\int \left (\frac{a^2 c^2}{x^{3/2}}+2 a c (b c+a d) \sqrt{x}+\left (b^2 c^2+4 a b c d+a^2 d^2\right ) x^{5/2}+2 b d (b c+a d) x^{9/2}+b^2 d^2 x^{13/2}\right ) \, dx\\ &=-\frac{2 a^2 c^2}{\sqrt{x}}+\frac{4}{3} a c (b c+a d) x^{3/2}+\frac{2}{7} \left (b^2 c^2+4 a b c d+a^2 d^2\right ) x^{7/2}+\frac{4}{11} b d (b c+a d) x^{11/2}+\frac{2}{15} b^2 d^2 x^{15/2}\\ \end{align*}

Mathematica [A]  time = 0.0316485, size = 83, normalized size = 0.87 \[ \frac{2 \left (165 x^4 \left (a^2 d^2+4 a b c d+b^2 c^2\right )-1155 a^2 c^2+210 b d x^6 (a d+b c)+770 a c x^2 (a d+b c)+77 b^2 d^2 x^8\right )}{1155 \sqrt{x}} \]

Antiderivative was successfully verified.

[In]

Integrate[((a + b*x^2)^2*(c + d*x^2)^2)/x^(3/2),x]

[Out]

(2*(-1155*a^2*c^2 + 770*a*c*(b*c + a*d)*x^2 + 165*(b^2*c^2 + 4*a*b*c*d + a^2*d^2)*x^4 + 210*b*d*(b*c + a*d)*x^
6 + 77*b^2*d^2*x^8))/(1155*Sqrt[x])

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Maple [A]  time = 0.004, size = 97, normalized size = 1. \begin{align*} -{\frac{-154\,{b}^{2}{d}^{2}{x}^{8}-420\,{x}^{6}ab{d}^{2}-420\,{x}^{6}{b}^{2}cd-330\,{x}^{4}{a}^{2}{d}^{2}-1320\,{x}^{4}abcd-330\,{x}^{4}{b}^{2}{c}^{2}-1540\,{x}^{2}{a}^{2}cd-1540\,a{c}^{2}b{x}^{2}+2310\,{a}^{2}{c}^{2}}{1155}{\frac{1}{\sqrt{x}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x^2+a)^2*(d*x^2+c)^2/x^(3/2),x)

[Out]

-2/1155*(-77*b^2*d^2*x^8-210*a*b*d^2*x^6-210*b^2*c*d*x^6-165*a^2*d^2*x^4-660*a*b*c*d*x^4-165*b^2*c^2*x^4-770*a
^2*c*d*x^2-770*a*b*c^2*x^2+1155*a^2*c^2)/x^(1/2)

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Maxima [A]  time = 1.0307, size = 115, normalized size = 1.21 \begin{align*} \frac{2}{15} \, b^{2} d^{2} x^{\frac{15}{2}} + \frac{4}{11} \,{\left (b^{2} c d + a b d^{2}\right )} x^{\frac{11}{2}} + \frac{2}{7} \,{\left (b^{2} c^{2} + 4 \, a b c d + a^{2} d^{2}\right )} x^{\frac{7}{2}} - \frac{2 \, a^{2} c^{2}}{\sqrt{x}} + \frac{4}{3} \,{\left (a b c^{2} + a^{2} c d\right )} x^{\frac{3}{2}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^2+a)^2*(d*x^2+c)^2/x^(3/2),x, algorithm="maxima")

[Out]

2/15*b^2*d^2*x^(15/2) + 4/11*(b^2*c*d + a*b*d^2)*x^(11/2) + 2/7*(b^2*c^2 + 4*a*b*c*d + a^2*d^2)*x^(7/2) - 2*a^
2*c^2/sqrt(x) + 4/3*(a*b*c^2 + a^2*c*d)*x^(3/2)

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Fricas [A]  time = 0.721341, size = 203, normalized size = 2.14 \begin{align*} \frac{2 \,{\left (77 \, b^{2} d^{2} x^{8} + 210 \,{\left (b^{2} c d + a b d^{2}\right )} x^{6} + 165 \,{\left (b^{2} c^{2} + 4 \, a b c d + a^{2} d^{2}\right )} x^{4} - 1155 \, a^{2} c^{2} + 770 \,{\left (a b c^{2} + a^{2} c d\right )} x^{2}\right )}}{1155 \, \sqrt{x}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^2+a)^2*(d*x^2+c)^2/x^(3/2),x, algorithm="fricas")

[Out]

2/1155*(77*b^2*d^2*x^8 + 210*(b^2*c*d + a*b*d^2)*x^6 + 165*(b^2*c^2 + 4*a*b*c*d + a^2*d^2)*x^4 - 1155*a^2*c^2
+ 770*(a*b*c^2 + a^2*c*d)*x^2)/sqrt(x)

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Sympy [A]  time = 5.54516, size = 134, normalized size = 1.41 \begin{align*} - \frac{2 a^{2} c^{2}}{\sqrt{x}} + \frac{4 a^{2} c d x^{\frac{3}{2}}}{3} + \frac{2 a^{2} d^{2} x^{\frac{7}{2}}}{7} + \frac{4 a b c^{2} x^{\frac{3}{2}}}{3} + \frac{8 a b c d x^{\frac{7}{2}}}{7} + \frac{4 a b d^{2} x^{\frac{11}{2}}}{11} + \frac{2 b^{2} c^{2} x^{\frac{7}{2}}}{7} + \frac{4 b^{2} c d x^{\frac{11}{2}}}{11} + \frac{2 b^{2} d^{2} x^{\frac{15}{2}}}{15} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x**2+a)**2*(d*x**2+c)**2/x**(3/2),x)

[Out]

-2*a**2*c**2/sqrt(x) + 4*a**2*c*d*x**(3/2)/3 + 2*a**2*d**2*x**(7/2)/7 + 4*a*b*c**2*x**(3/2)/3 + 8*a*b*c*d*x**(
7/2)/7 + 4*a*b*d**2*x**(11/2)/11 + 2*b**2*c**2*x**(7/2)/7 + 4*b**2*c*d*x**(11/2)/11 + 2*b**2*d**2*x**(15/2)/15

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Giac [A]  time = 1.62242, size = 127, normalized size = 1.34 \begin{align*} \frac{2}{15} \, b^{2} d^{2} x^{\frac{15}{2}} + \frac{4}{11} \, b^{2} c d x^{\frac{11}{2}} + \frac{4}{11} \, a b d^{2} x^{\frac{11}{2}} + \frac{2}{7} \, b^{2} c^{2} x^{\frac{7}{2}} + \frac{8}{7} \, a b c d x^{\frac{7}{2}} + \frac{2}{7} \, a^{2} d^{2} x^{\frac{7}{2}} + \frac{4}{3} \, a b c^{2} x^{\frac{3}{2}} + \frac{4}{3} \, a^{2} c d x^{\frac{3}{2}} - \frac{2 \, a^{2} c^{2}}{\sqrt{x}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^2+a)^2*(d*x^2+c)^2/x^(3/2),x, algorithm="giac")

[Out]

2/15*b^2*d^2*x^(15/2) + 4/11*b^2*c*d*x^(11/2) + 4/11*a*b*d^2*x^(11/2) + 2/7*b^2*c^2*x^(7/2) + 8/7*a*b*c*d*x^(7
/2) + 2/7*a^2*d^2*x^(7/2) + 4/3*a*b*c^2*x^(3/2) + 4/3*a^2*c*d*x^(3/2) - 2*a^2*c^2/sqrt(x)